## Rate Equation for the Zero Order Reaction:

Consider the general reaction-

A ———-> Products |

Let [A]_{0} be the initial concentration of ‘A’ and [A] is the concentration at time ‘t’ sec.

As it is a zero-order reaction-

Rate = -d[A]/dt = k[A]^{°} = k_{0} [Where ‘k_{0}‘ is rate constant of zero orderor -d[A] = k _{0} dt ………(i)Integrating both sides of the equation (i), we get + ∫d[A] = -k _{0} ∫dt⇒ + [A] = -k _{0} . t + I ………(ii) [Where ‘I’ is constant of integration]When t = 0 ; [A] = [A] _{0}∴ [A] _{0} = I ………(iii)Put equation (iii) in equation (ii), we get- [A] = -k _{0} . t + [A]_{0}or k _{0} . t = [A]_{0} – [A] ⇒ k _{0} = 1/t {[A]_{0} – [A]}It is an integrated rate equation for zero order reaction. Units of k _{0} = (1/sec) (mole/litre) = mole litre^{-1} sec^{-1} |