Rate Equation for the Zero Order Reaction:
Consider the general reaction-
| A ———-> Products |
Let [A]0 be the initial concentration of ‘A’ and [A] is the concentration at time ‘t’ sec.
As it is a zero-order reaction-
| Rate = -d[A]/dt = k[A]° = k0 [Where ‘k0‘ is rate constant of zero order or -d[A] = k0 dt ………(i) Integrating both sides of the equation (i), we get + ∫d[A] = -k0 ∫dt ⇒ + [A] = -k0 . t + I ………(ii) [Where ‘I’ is constant of integration] When t = 0 ; [A] = [A]0 ∴ [A]0 = I ………(iii) Put equation (iii) in equation (ii), we get- [A] = -k0 . t + [A]0 or k0 . t = [A]0 – [A] ⇒ k0 = 1/t {[A]0 – [A]} It is an integrated rate equation for zero order reaction. Units of k0 = (1/sec) (mole/litre) = mole litre-1 sec-1 |
